Saturday, March 3, 2018

javascript - jQuery Ajax POST example with PHP



I am trying to send data from a form to a database. Here is the form I am using:











The typical approach would be to submit the form, but this causes the browser to redirect. Using jQuery and Ajax, is it possible to capture all of the form's data and submit it to a PHP script (an example, form.php)?


Answer



Basic usage of .ajax would look something like this:



HTML:












jQuery:



// Variable to hold request
var request;


// Bind to the submit event of our form
$("#foo").submit(function(event){

// Prevent default posting of form - put here to work in case of errors
event.preventDefault();

// Abort any pending request
if (request) {
request.abort();
}

// setup some local variables
var $form = $(this);

// Let's select and cache all the fields
var $inputs = $form.find("input, select, button, textarea");

// Serialize the data in the form
var serializedData = $form.serialize();

// Let's disable the inputs for the duration of the Ajax request.

// Note: we disable elements AFTER the form data has been serialized.
// Disabled form elements will not be serialized.
$inputs.prop("disabled", true);

// Fire off the request to /form.php
request = $.ajax({
url: "/form.php",
type: "post",
data: serializedData
});


// Callback handler that will be called on success
request.done(function (response, textStatus, jqXHR){
// Log a message to the console
console.log("Hooray, it worked!");
});

// Callback handler that will be called on failure
request.fail(function (jqXHR, textStatus, errorThrown){
// Log the error to the console

console.error(
"The following error occurred: "+
textStatus, errorThrown
);
});

// Callback handler that will be called regardless
// if the request failed or succeeded
request.always(function () {
// Reenable the inputs

$inputs.prop("disabled", false);
});

});


Note: Since jQuery 1.8, .success(), .error() and .complete() are deprecated in favor of .done(), .fail() and .always().



Note: Remember that the above snippet has to be done after DOM ready, so you should put it inside a $(document).ready() handler (or use the $() shorthand).




Tip: You can chain the callback handlers like this: $.ajax().done().fail().always();



PHP (that is, form.php):



// You can access the values posted by jQuery.ajax
// through the global variable $_POST, like this:
$bar = isset($_POST['bar']) ? $_POST['bar'] : null;


Note: Always sanitize posted data, to prevent injections and other malicious code.




You could also use the shorthand .post in place of .ajax in the above JavaScript code:



$.post('/form.php', serializedData, function(response) {
// Log the response to the console
console.log("Response: "+response);
});


Note: The above JavaScript code is made to work with jQuery 1.8 and later, but it should work with previous versions down to jQuery 1.5.



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