bash - Difference between single and double quotes in awk

I have this awk statement:

glb_library="my_library"
awk "

        /^Direct Dependers of/ { next }
        /^---/                 { next }
        /^$glb_library:/       { ver=\$0; next }
                               { gsub(/[[:space:]]/, '', \$0); print ver':'\$0 }
      " file

Basically, I have enclosed the awk code in double quotes so that the shell variable glb_library is expanded. I have made sure to escape the $ character to prevent the shell from expanding $0. Followed the guidance from here.

awk gives me this error:

awk: syntax error at source line 5
 context is
                                   { gsub(/[[:space:]]/, >>>  ' <<<

I want to understand:

• Is it legal to use single quotes inside awk? Why is '' not a null string like "" is?



• Does awk treat single and double quotes differently?

My code worked after I escaped the single quotes with backslashes and used \"\" to represent the null string instead of ''.

Answer

Based on the comments above by awk experts and some research, I am posting this answer:

• awk strings are enclosed in double quotes, not single quotes; more precisely: single quotes are not string delimiters in awk, unlike shell


• awk attaches no special meaning to single quotes and they need to be enclosed in double quotes if used in string literals



• it is best to use single quotes to wrap awk statements on command line, unlike OP's code that's using double quotes (Ed pointed this out clearly)

Further clarification:

• "" is the null string in awk, not ''


• to use single quotes in an awk string literal, enclose them in double quotes, as in "Ed's answers are great!"



• other techniques followed while handling single quotes in awk are:

  
  
  
  

  a) use a variable, as in awk -v q="'" '{ print q }' ...

  
  
  

  b) use octal or hex notation, as in awk '{ print "\047"$0"\047" }' ...

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Relevant documentation here.