Saturday, July 28, 2018

c++ - How do I achieve the theoretical maximum of 4 FLOPs per cycle?



How can the theoretical peak performance of 4 floating point operations (double precision) per cycle be achieved on a modern x86-64 Intel CPU?



As far as I understand it take three cycles for an SSE add and five cycles for a mul to complete on most of the modern Intel CPUs (see for example Agner Fog's 'Instruction Tables' ). Due to pipelining one can get a throughput of one add per cycle if the algorithm has at least three independent summations. Since that is true for packed addpd as well as the scalar addsd versions and SSE registers can contain two double's the throughput can be as much as two flops per cycle.



Furthermore, it seems (although I've not seen any proper documentation on this) add's and mul's can be executed in parallel giving a theoretical max throughput of four flops per cycle.




However, I've not been able to replicate that performance with a simple C/C++ programme. My best attempt resulted in about 2.7 flops/cycle. If anyone can contribute a simple C/C++ or assembler programme which demonstrates peak performance that'd be greatly appreciated.



My attempt:



#include 
#include
#include
#include


double stoptime(void) {
struct timeval t;
gettimeofday(&t,NULL);
return (double) t.tv_sec + t.tv_usec/1000000.0;
}

double addmul(double add, double mul, int ops){
// Need to initialise differently otherwise compiler might optimise away
double sum1=0.1, sum2=-0.1, sum3=0.2, sum4=-0.2, sum5=0.0;
double mul1=1.0, mul2= 1.1, mul3=1.2, mul4= 1.3, mul5=1.4;

int loops=ops/10; // We have 10 floating point operations inside the loop
double expected = 5.0*add*loops + (sum1+sum2+sum3+sum4+sum5)
+ pow(mul,loops)*(mul1+mul2+mul3+mul4+mul5);

for (int i=0; i mul1*=mul; mul2*=mul; mul3*=mul; mul4*=mul; mul5*=mul;
sum1+=add; sum2+=add; sum3+=add; sum4+=add; sum5+=add;
}
return sum1+sum2+sum3+sum4+sum5+mul1+mul2+mul3+mul4+mul5 - expected;
}


int main(int argc, char** argv) {
if (argc != 2) {
printf("usage: %s \n", argv[0]);
printf("number of operations: millions\n");
exit(EXIT_FAILURE);
}
int n = atoi(argv[1]) * 1000000;
if (n<=0)
n=1000;


double x = M_PI;
double y = 1.0 + 1e-8;
double t = stoptime();
x = addmul(x, y, n);
t = stoptime() - t;
printf("addmul:\t %.3f s, %.3f Gflops, res=%f\n", t, (double)n/t/1e9, x);
return EXIT_SUCCESS;
}



Compiled with



g++ -O2 -march=native addmul.cpp ; ./a.out 1000


produces the following output on an Intel Core i5-750, 2.66 GHz.



addmul:  0.270 s, 3.707 Gflops, res=1.326463



That is, just about 1.4 flops per cycle. Looking at the assembler code with
g++ -S -O2 -march=native -masm=intel addmul.cpp the main loop seems kind of
optimal to me:



.L4:
inc eax
mulsd xmm8, xmm3
mulsd xmm7, xmm3
mulsd xmm6, xmm3

mulsd xmm5, xmm3
mulsd xmm1, xmm3
addsd xmm13, xmm2
addsd xmm12, xmm2
addsd xmm11, xmm2
addsd xmm10, xmm2
addsd xmm9, xmm2
cmp eax, ebx
jne .L4



Changing the scalar versions with packed versions (addpd and mulpd) would double the flop count without changing the execution time and so I'd get just short of 2.8 flops per cycle. Is there a simple example which achieves four flops per cycle?



Nice little programme by Mysticial; here are my results (run just for a few seconds though):




  • gcc -O2 -march=nocona: 5.6 Gflops out of 10.66 Gflops (2.1 flops/cycle)

  • cl /O2, openmp removed: 10.1 Gflops out of 10.66 Gflops (3.8 flops/cycle)




It all seems a bit complex, but my conclusions so far:




  • gcc -O2 changes the order of independent floating point operations with
    the aim of alternating
    addpd and mulpd's if possible. Same applies to gcc-4.6.2 -O2 -march=core2.


  • gcc -O2 -march=nocona seems to keep the order of floating point operations as defined in
    the C++ source.


  • cl /O2, the 64-bit compiler from the
    SDK for Windows 7

    does loop-unrolling automatically and seems to try and arrange operations
    so that groups of three addpd's alternate with three mulpd's (well, at least on my system and for my simple programme).


  • My Core i5 750 (Nehalem architecture)
    doesn't like alternating add's and mul's and seems unable
    to run both operations in parallel. However, if grouped in 3's it suddenly works like magic.


  • Other architectures (possibly Sandy Bridge and others) appear to
    be able to execute add/mul in parallel without problems
    if they alternate in the assembly code.


  • Although difficult to admit, but on my system cl /O2 does a much better job at low-level optimising operations for my system and achieves close to peak performance for the little C++ example above. I measured between
    1.85-2.01 flops/cycle (have used clock() in Windows which is not that precise. I guess, need to use a better timer - thanks Mackie Messer).



  • The best I managed with gcc was to manually loop unroll and arrange
    additions and multiplications in groups of three. With
    g++ -O2 -march=nocona addmul_unroll.cpp
    I get at best 0.207s, 4.825 Gflops which corresponds to 1.8 flops/cycle
    which I'm quite happy with now.




In the C++ code I've replaced the for loop with



   for (int i=0; i
mul1*=mul; mul2*=mul; mul3*=mul;
sum1+=add; sum2+=add; sum3+=add;
mul4*=mul; mul5*=mul; mul1*=mul;
sum4+=add; sum5+=add; sum1+=add;

mul2*=mul; mul3*=mul; mul4*=mul;
sum2+=add; sum3+=add; sum4+=add;
mul5*=mul; mul1*=mul; mul2*=mul;
sum5+=add; sum1+=add; sum2+=add;


mul3*=mul; mul4*=mul; mul5*=mul;
sum3+=add; sum4+=add; sum5+=add;
}


And the assembly now looks like



.L4:
mulsd xmm8, xmm3
mulsd xmm7, xmm3

mulsd xmm6, xmm3
addsd xmm13, xmm2
addsd xmm12, xmm2
addsd xmm11, xmm2
mulsd xmm5, xmm3
mulsd xmm1, xmm3
mulsd xmm8, xmm3
addsd xmm10, xmm2
addsd xmm9, xmm2
addsd xmm13, xmm2

...

Answer



I've done this exact task before. But it was mainly to measure power consumption and CPU temperatures. The following code (which is fairly long) achieves close to optimal on my Core i7 2600K.



The key thing to note here is the massive amount of manual loop-unrolling as well as interleaving of multiplies and adds...



The full project can be found on my GitHub: https://github.com/Mysticial/Flops






If you decide to compile and run this, pay attention to your CPU temperatures!!!
Make sure you don't overheat it. And make sure CPU-throttling doesn't affect your results!



Furthermore, I take no responsibility for whatever damage that may result from running this code.



Notes:




  • This code is optimized for x64. x86 doesn't have enough registers for this to compile well.

  • This code has been tested to work well on Visual Studio 2010/2012 and GCC 4.6.
    ICC 11 (Intel Compiler 11) surprisingly has trouble compiling it well.


  • These are for pre-FMA processors. In order to achieve peak FLOPS on Intel Haswell and AMD Bulldozer processors (and later), FMA (Fused Multiply Add) instructions will be needed. These are beyond the scope of this benchmark.





#include 
#include
#include
using namespace std;


typedef unsigned long long uint64;

double test_dp_mac_SSE(double x,double y,uint64 iterations){
register __m128d r0,r1,r2,r3,r4,r5,r6,r7,r8,r9,rA,rB,rC,rD,rE,rF;

// Generate starting data.
r0 = _mm_set1_pd(x);
r1 = _mm_set1_pd(y);

r8 = _mm_set1_pd(-0.0);


r2 = _mm_xor_pd(r0,r8);
r3 = _mm_or_pd(r0,r8);
r4 = _mm_andnot_pd(r8,r0);
r5 = _mm_mul_pd(r1,_mm_set1_pd(0.37796447300922722721));
r6 = _mm_mul_pd(r1,_mm_set1_pd(0.24253562503633297352));
r7 = _mm_mul_pd(r1,_mm_set1_pd(4.1231056256176605498));
r8 = _mm_add_pd(r0,_mm_set1_pd(0.37796447300922722721));
r9 = _mm_add_pd(r1,_mm_set1_pd(0.24253562503633297352));
rA = _mm_sub_pd(r0,_mm_set1_pd(4.1231056256176605498));

rB = _mm_sub_pd(r1,_mm_set1_pd(4.1231056256176605498));

rC = _mm_set1_pd(1.4142135623730950488);
rD = _mm_set1_pd(1.7320508075688772935);
rE = _mm_set1_pd(0.57735026918962576451);
rF = _mm_set1_pd(0.70710678118654752440);

uint64 iMASK = 0x800fffffffffffffull;
__m128d MASK = _mm_set1_pd(*(double*)&iMASK);
__m128d vONE = _mm_set1_pd(1.0);


uint64 c = 0;
while (c < iterations){
size_t i = 0;
while (i < 1000){
// Here's the meat - the part that really matters.

r0 = _mm_mul_pd(r0,rC);
r1 = _mm_add_pd(r1,rD);
r2 = _mm_mul_pd(r2,rE);

r3 = _mm_sub_pd(r3,rF);
r4 = _mm_mul_pd(r4,rC);
r5 = _mm_add_pd(r5,rD);
r6 = _mm_mul_pd(r6,rE);
r7 = _mm_sub_pd(r7,rF);
r8 = _mm_mul_pd(r8,rC);
r9 = _mm_add_pd(r9,rD);
rA = _mm_mul_pd(rA,rE);
rB = _mm_sub_pd(rB,rF);


r0 = _mm_add_pd(r0,rF);
r1 = _mm_mul_pd(r1,rE);
r2 = _mm_sub_pd(r2,rD);
r3 = _mm_mul_pd(r3,rC);
r4 = _mm_add_pd(r4,rF);
r5 = _mm_mul_pd(r5,rE);
r6 = _mm_sub_pd(r6,rD);
r7 = _mm_mul_pd(r7,rC);
r8 = _mm_add_pd(r8,rF);
r9 = _mm_mul_pd(r9,rE);

rA = _mm_sub_pd(rA,rD);
rB = _mm_mul_pd(rB,rC);

r0 = _mm_mul_pd(r0,rC);
r1 = _mm_add_pd(r1,rD);
r2 = _mm_mul_pd(r2,rE);
r3 = _mm_sub_pd(r3,rF);
r4 = _mm_mul_pd(r4,rC);
r5 = _mm_add_pd(r5,rD);
r6 = _mm_mul_pd(r6,rE);

r7 = _mm_sub_pd(r7,rF);
r8 = _mm_mul_pd(r8,rC);
r9 = _mm_add_pd(r9,rD);
rA = _mm_mul_pd(rA,rE);
rB = _mm_sub_pd(rB,rF);

r0 = _mm_add_pd(r0,rF);
r1 = _mm_mul_pd(r1,rE);
r2 = _mm_sub_pd(r2,rD);
r3 = _mm_mul_pd(r3,rC);

r4 = _mm_add_pd(r4,rF);
r5 = _mm_mul_pd(r5,rE);
r6 = _mm_sub_pd(r6,rD);
r7 = _mm_mul_pd(r7,rC);
r8 = _mm_add_pd(r8,rF);
r9 = _mm_mul_pd(r9,rE);
rA = _mm_sub_pd(rA,rD);
rB = _mm_mul_pd(rB,rC);

i++;

}

// Need to renormalize to prevent denormal/overflow.
r0 = _mm_and_pd(r0,MASK);
r1 = _mm_and_pd(r1,MASK);
r2 = _mm_and_pd(r2,MASK);
r3 = _mm_and_pd(r3,MASK);
r4 = _mm_and_pd(r4,MASK);
r5 = _mm_and_pd(r5,MASK);
r6 = _mm_and_pd(r6,MASK);

r7 = _mm_and_pd(r7,MASK);
r8 = _mm_and_pd(r8,MASK);
r9 = _mm_and_pd(r9,MASK);
rA = _mm_and_pd(rA,MASK);
rB = _mm_and_pd(rB,MASK);
r0 = _mm_or_pd(r0,vONE);
r1 = _mm_or_pd(r1,vONE);
r2 = _mm_or_pd(r2,vONE);
r3 = _mm_or_pd(r3,vONE);
r4 = _mm_or_pd(r4,vONE);

r5 = _mm_or_pd(r5,vONE);
r6 = _mm_or_pd(r6,vONE);
r7 = _mm_or_pd(r7,vONE);
r8 = _mm_or_pd(r8,vONE);
r9 = _mm_or_pd(r9,vONE);
rA = _mm_or_pd(rA,vONE);
rB = _mm_or_pd(rB,vONE);

c++;
}


r0 = _mm_add_pd(r0,r1);
r2 = _mm_add_pd(r2,r3);
r4 = _mm_add_pd(r4,r5);
r6 = _mm_add_pd(r6,r7);
r8 = _mm_add_pd(r8,r9);
rA = _mm_add_pd(rA,rB);

r0 = _mm_add_pd(r0,r2);
r4 = _mm_add_pd(r4,r6);

r8 = _mm_add_pd(r8,rA);

r0 = _mm_add_pd(r0,r4);
r0 = _mm_add_pd(r0,r8);


// Prevent Dead Code Elimination
double out = 0;
__m128d temp = r0;
out += ((double*)&temp)[0];

out += ((double*)&temp)[1];

return out;
}

void test_dp_mac_SSE(int tds,uint64 iterations){

double *sum = (double*)malloc(tds * sizeof(double));
double start = omp_get_wtime();


#pragma omp parallel num_threads(tds)
{
double ret = test_dp_mac_SSE(1.1,2.1,iterations);
sum[omp_get_thread_num()] = ret;
}

double secs = omp_get_wtime() - start;
uint64 ops = 48 * 1000 * iterations * tds * 2;
cout << "Seconds = " << secs << endl;
cout << "FP Ops = " << ops << endl;

cout << "FLOPs = " << ops / secs << endl;

double out = 0;
int c = 0;
while (c < tds){
out += sum[c++];
}

cout << "sum = " << out << endl;
cout << endl;


free(sum);
}

int main(){
// (threads, iterations)
test_dp_mac_SSE(8,10000000);

system("pause");
}



Output (1 thread, 10000000 iterations) - Compiled with Visual Studio 2010 SP1 - x64 Release:



Seconds = 55.5104
FP Ops = 960000000000
FLOPs = 1.7294e+010
sum = 2.22652



The machine is a Core i7 2600K @ 4.4 GHz. Theoretical SSE peak is 4 flops * 4.4 GHz = 17.6 GFlops. This code achieves 17.3 GFlops - not bad.



Output (8 threads, 10000000 iterations) - Compiled with Visual Studio 2010 SP1 - x64 Release:



Seconds = 117.202
FP Ops = 7680000000000
FLOPs = 6.55279e+010
sum = 17.8122



Theoretical SSE peak is 4 flops * 4 cores * 4.4 GHz = 70.4 GFlops. Actual is 65.5 GFlops.






Let's take this one step further. AVX...



#include 
#include
#include
using namespace std;


typedef unsigned long long uint64;

double test_dp_mac_AVX(double x,double y,uint64 iterations){
register __m256d r0,r1,r2,r3,r4,r5,r6,r7,r8,r9,rA,rB,rC,rD,rE,rF;

// Generate starting data.
r0 = _mm256_set1_pd(x);
r1 = _mm256_set1_pd(y);


r8 = _mm256_set1_pd(-0.0);

r2 = _mm256_xor_pd(r0,r8);
r3 = _mm256_or_pd(r0,r8);
r4 = _mm256_andnot_pd(r8,r0);
r5 = _mm256_mul_pd(r1,_mm256_set1_pd(0.37796447300922722721));
r6 = _mm256_mul_pd(r1,_mm256_set1_pd(0.24253562503633297352));
r7 = _mm256_mul_pd(r1,_mm256_set1_pd(4.1231056256176605498));
r8 = _mm256_add_pd(r0,_mm256_set1_pd(0.37796447300922722721));
r9 = _mm256_add_pd(r1,_mm256_set1_pd(0.24253562503633297352));

rA = _mm256_sub_pd(r0,_mm256_set1_pd(4.1231056256176605498));
rB = _mm256_sub_pd(r1,_mm256_set1_pd(4.1231056256176605498));

rC = _mm256_set1_pd(1.4142135623730950488);
rD = _mm256_set1_pd(1.7320508075688772935);
rE = _mm256_set1_pd(0.57735026918962576451);
rF = _mm256_set1_pd(0.70710678118654752440);

uint64 iMASK = 0x800fffffffffffffull;
__m256d MASK = _mm256_set1_pd(*(double*)&iMASK);

__m256d vONE = _mm256_set1_pd(1.0);

uint64 c = 0;
while (c < iterations){
size_t i = 0;
while (i < 1000){
// Here's the meat - the part that really matters.

r0 = _mm256_mul_pd(r0,rC);
r1 = _mm256_add_pd(r1,rD);

r2 = _mm256_mul_pd(r2,rE);
r3 = _mm256_sub_pd(r3,rF);
r4 = _mm256_mul_pd(r4,rC);
r5 = _mm256_add_pd(r5,rD);
r6 = _mm256_mul_pd(r6,rE);
r7 = _mm256_sub_pd(r7,rF);
r8 = _mm256_mul_pd(r8,rC);
r9 = _mm256_add_pd(r9,rD);
rA = _mm256_mul_pd(rA,rE);
rB = _mm256_sub_pd(rB,rF);


r0 = _mm256_add_pd(r0,rF);
r1 = _mm256_mul_pd(r1,rE);
r2 = _mm256_sub_pd(r2,rD);
r3 = _mm256_mul_pd(r3,rC);
r4 = _mm256_add_pd(r4,rF);
r5 = _mm256_mul_pd(r5,rE);
r6 = _mm256_sub_pd(r6,rD);
r7 = _mm256_mul_pd(r7,rC);
r8 = _mm256_add_pd(r8,rF);

r9 = _mm256_mul_pd(r9,rE);
rA = _mm256_sub_pd(rA,rD);
rB = _mm256_mul_pd(rB,rC);

r0 = _mm256_mul_pd(r0,rC);
r1 = _mm256_add_pd(r1,rD);
r2 = _mm256_mul_pd(r2,rE);
r3 = _mm256_sub_pd(r3,rF);
r4 = _mm256_mul_pd(r4,rC);
r5 = _mm256_add_pd(r5,rD);

r6 = _mm256_mul_pd(r6,rE);
r7 = _mm256_sub_pd(r7,rF);
r8 = _mm256_mul_pd(r8,rC);
r9 = _mm256_add_pd(r9,rD);
rA = _mm256_mul_pd(rA,rE);
rB = _mm256_sub_pd(rB,rF);

r0 = _mm256_add_pd(r0,rF);
r1 = _mm256_mul_pd(r1,rE);
r2 = _mm256_sub_pd(r2,rD);

r3 = _mm256_mul_pd(r3,rC);
r4 = _mm256_add_pd(r4,rF);
r5 = _mm256_mul_pd(r5,rE);
r6 = _mm256_sub_pd(r6,rD);
r7 = _mm256_mul_pd(r7,rC);
r8 = _mm256_add_pd(r8,rF);
r9 = _mm256_mul_pd(r9,rE);
rA = _mm256_sub_pd(rA,rD);
rB = _mm256_mul_pd(rB,rC);


i++;
}

// Need to renormalize to prevent denormal/overflow.
r0 = _mm256_and_pd(r0,MASK);
r1 = _mm256_and_pd(r1,MASK);
r2 = _mm256_and_pd(r2,MASK);
r3 = _mm256_and_pd(r3,MASK);
r4 = _mm256_and_pd(r4,MASK);
r5 = _mm256_and_pd(r5,MASK);

r6 = _mm256_and_pd(r6,MASK);
r7 = _mm256_and_pd(r7,MASK);
r8 = _mm256_and_pd(r8,MASK);
r9 = _mm256_and_pd(r9,MASK);
rA = _mm256_and_pd(rA,MASK);
rB = _mm256_and_pd(rB,MASK);
r0 = _mm256_or_pd(r0,vONE);
r1 = _mm256_or_pd(r1,vONE);
r2 = _mm256_or_pd(r2,vONE);
r3 = _mm256_or_pd(r3,vONE);

r4 = _mm256_or_pd(r4,vONE);
r5 = _mm256_or_pd(r5,vONE);
r6 = _mm256_or_pd(r6,vONE);
r7 = _mm256_or_pd(r7,vONE);
r8 = _mm256_or_pd(r8,vONE);
r9 = _mm256_or_pd(r9,vONE);
rA = _mm256_or_pd(rA,vONE);
rB = _mm256_or_pd(rB,vONE);

c++;

}

r0 = _mm256_add_pd(r0,r1);
r2 = _mm256_add_pd(r2,r3);
r4 = _mm256_add_pd(r4,r5);
r6 = _mm256_add_pd(r6,r7);
r8 = _mm256_add_pd(r8,r9);
rA = _mm256_add_pd(rA,rB);

r0 = _mm256_add_pd(r0,r2);

r4 = _mm256_add_pd(r4,r6);
r8 = _mm256_add_pd(r8,rA);

r0 = _mm256_add_pd(r0,r4);
r0 = _mm256_add_pd(r0,r8);

// Prevent Dead Code Elimination
double out = 0;
__m256d temp = r0;
out += ((double*)&temp)[0];

out += ((double*)&temp)[1];
out += ((double*)&temp)[2];
out += ((double*)&temp)[3];

return out;
}

void test_dp_mac_AVX(int tds,uint64 iterations){

double *sum = (double*)malloc(tds * sizeof(double));

double start = omp_get_wtime();

#pragma omp parallel num_threads(tds)
{
double ret = test_dp_mac_AVX(1.1,2.1,iterations);
sum[omp_get_thread_num()] = ret;
}

double secs = omp_get_wtime() - start;
uint64 ops = 48 * 1000 * iterations * tds * 4;

cout << "Seconds = " << secs << endl;
cout << "FP Ops = " << ops << endl;
cout << "FLOPs = " << ops / secs << endl;

double out = 0;
int c = 0;
while (c < tds){
out += sum[c++];
}


cout << "sum = " << out << endl;
cout << endl;

free(sum);
}

int main(){
// (threads, iterations)
test_dp_mac_AVX(8,10000000);


system("pause");
}


Output (1 thread, 10000000 iterations) - Compiled with Visual Studio 2010 SP1 - x64 Release:



Seconds = 57.4679
FP Ops = 1920000000000
FLOPs = 3.34099e+010
sum = 4.45305



Theoretical AVX peak is 8 flops * 4.4 GHz = 35.2 GFlops. Actual is 33.4 GFlops.



Output (8 threads, 10000000 iterations) - Compiled with Visual Studio 2010 SP1 - x64 Release:



Seconds = 111.119
FP Ops = 15360000000000
FLOPs = 1.3823e+011
sum = 35.6244



Theoretical AVX peak is 8 flops * 4 cores * 4.4 GHz = 140.8 GFlops. Actual is 138.2 GFlops.






Now for some explanations:



The performance critical part is obviously the 48 instructions inside the inner loop. You'll notice that it's broken into 4 blocks of 12 instructions each. Each of these 12 instructions blocks are completely independent from each other - and take on average 6 cycles to execute.




So there's 12 instructions and 6 cycles between issue-to-use. The latency of multiplication is 5 cycles, so it's just enough to avoid latency stalls.



The normalization step is needed to keep the data from over/underflowing. This is needed since the do-nothing code will slowly increase/decrease the magnitude of the data.



So it's actually possible to do better than this if you just use all zeros and get rid of the normalization step. However, since I wrote the benchmark to measure power consumption and temperature, I had to make sure the flops were on "real" data, rather than zeros - as the execution units may very well have special case-handling for zeros that use less power and produce less heat.






More Results:





  • Intel Core i7 920 @ 3.5 GHz

  • Windows 7 Ultimate x64

  • Visual Studio 2010 SP1 - x64 Release



Threads: 1



Seconds = 72.1116
FP Ops = 960000000000

FLOPs = 1.33127e+010
sum = 2.22652


Theoretical SSE Peak: 4 flops * 3.5 GHz = 14.0 GFlops. Actual is 13.3 GFlops.



Threads: 8



Seconds = 149.576
FP Ops = 7680000000000

FLOPs = 5.13452e+010
sum = 17.8122


Theoretical SSE Peak: 4 flops * 4 cores * 3.5 GHz = 56.0 GFlops. Actual is 51.3 GFlops.



My processor temps hit 76C on the multi-threaded run! If you runs these, be sure the results aren't affected by CPU throttling.








  • 2 x Intel Xeon X5482 Harpertown @ 3.2 GHz

  • Ubuntu Linux 10 x64

  • GCC 4.5.2 x64 - (-O2 -msse3 -fopenmp)



Threads: 1



Seconds = 78.3357
FP Ops = 960000000000

FLOPs = 1.22549e+10
sum = 2.22652


Theoretical SSE Peak: 4 flops * 3.2 GHz = 12.8 GFlops. Actual is 12.3 GFlops.



Threads: 8



Seconds = 78.4733
FP Ops = 7680000000000

FLOPs = 9.78676e+10
sum = 17.8122


Theoretical SSE Peak: 4 flops * 8 cores * 3.2 GHz = 102.4 GFlops. Actual is 97.9 GFlops.


No comments:

Post a Comment

plot explanation - Why did Peaches&#39; mom hang on the tree? - Movies &amp; TV

In the middle of the movie Ice Age: Continental Drift Peaches' mom asked Peaches to go to sleep. Then, she hung on the tree. This parti...