In my code, I use variadic template functions for the logging purpose. But when I use std::endl
as parameter, I get the following compiler error:
Error: no matching function for call to 'LOG_ERROR(const char [14],
int&, )' LOG_ERROR("Sum of x+y
= ", z, std::endl);
note: candidate: 'void LOG_ERROR()' inline void LOG_ERROR() {
note: candidate expects 0 arguments, 3 provided
My Code:
#include
inline void LOG_ERROR() {
std::cout << std::endl;
}
template
void LOG_ERROR(First && first, Rest && ...rest){
std::cout << std::forward(first);
LOG_ERROR(std::forward(rest)...);
}
int main() {
int foo=40;
LOG_ERROR("My foo = ", foo, std::endl);
}
The code works fine with "\n"
but I would love to learn why it fails with std::endl
and how I can fix it
Answer
std::endl
is not a character type or any other type. It is output stream manipulator. Its return type is output stream.
So, you can not pass it without typecasting. Please look here
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