Insert data mysqli and php in form 1 and return to new form 2

Hi all I am new to mysqli and php (currently studying and trying to work on a test database- I have not used security measures at this wont be available public) and trying to get the information I have just submitted in the form to display in a new form which will then receive further user input then submitted to database. Here is an example of what I have done so far:

Form 1 (customer table - cust id =primary key)

Customer Details ie name address telephone etc
dynamic drop down box - consists of 4 options.( would like whatever option is selected here to return a particular form)

The form is currently submitting correctly in the database, but I would like once it has submitted to the database to return the customer info (including the customer id as that is the relationship in the new table) and on the form2(service table - service id is primary key) so the user can input further data to the form and submit.

Hope this makes sense, any help would be appreciated.
Thanks

Response 1
Thank you for my response I probably havent made myself very clear.

Form 1 where dynamic dropdown list is - when user submits forms I would like it to return form 2 with the customer info we inserted in form 1

Form 1

    
    




First Name: 
    Last Name: 
    
Business Name: 
Contact Number: 
 Alt Number: 
Email Address:
  
Street No:

   Street Name:
    
Suburb:
  Postal Code:
    State: 

     **
Type of Service Required:  
---Select Service---
$servername = "";

$username = "";
$password = "";
$dbname = "";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 


$sql = "SELECT * FROM serviceType";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
       echo '' . $row['jobType'] . '';
    }
} else {

    echo "0 results";
}
$conn->close();
?>

 
 

    

       
   

Query in separate file

$fname=$_POST['firstname'];
$lname=$_POST['lastname'];

$bname=$_POST['businessname'];
$phone=$_POST['number'];
$altphone=$_POST['altno'];
$email=$_POST['email'];
$streetno=$_POST['streetno'];
$street=$_POST['street'];
$suburb=$_POST['suburb'];
$postcode=$_POST['postalcode'];
$state=$_POST['state'];
$service=$_POST['category'];





// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
} 


$sql = "INSERT INTO customer (contactFirstName,contactLastName,businessName,contactNumber,altNumber,email,streetNo,streetName,suburb,postalCode,state,serviceType)
VALUES ('$fname','$lname','$bname','$phone','$altphone','$email','$streetno','$street','$suburb','$postcode','$state','$service')";



if ($conn->query($sql) === TRUE) {
    echo "New record created successfully";
} else {
    echo "Error: " . $sql . "
" . $conn->error;

}
$conn->close();
?>