php - Trying to pass value to ISSET condition but getting error

I have created a PHP script and if use the script its always going to else condition and I am not sure why its not going to else condition.

     require_once  'db_functions.php';
   $db = new DB_Functions();
   $response = array();
   $phone="1234";
   $name="Test";
   $birthdate="1994-01-01";
   $address="123 M";
    if(isset($_POST['phone']) &&
    isset($_POST['name']) &&
    isset($_POST['birthdate']) &&
    isset($_POST['address']))
   {
    echo "Hello World 1";
    $phone = $_POST['phone'];
    $name = $_POST['name'];
    $birthdate = $_POST['birthdate'];
    $address = $_POST['address'];
    echo "Hello World 2";
   }
   else{
    echo "Hello";
    $response["error_msg"] = "Required parameter
    (phone,name,birthdate,address) is missing!";
    echo json_encode($response);
    }
    ?>

Output:

_msg":"Required parameter (phone,name,birthdate,address) is missing!"}

If the value is passed then it should go to if condition instead of else condition.

Options Tried

Tried Below options but I am getting empty value:

$test=$_POST['phone'];
echo "Hey......".$test;

echo isset($_POST['phone']);

URL USED
https://www.aaa.ccc/php/register.php?phone=232&name=test&birthdate=1954-04-04&address=232