Sunday, December 23, 2018

c++ - Practical Use of Zero-Length Bitfields



I am not totally sure about C, but C++ allows unnamed bit-fields of 0 length. For example:



struct X

{
int : 0;
};



  • Question one: What practical uses of this can you think of?

  • Question two: What real-world practical uses (if any) are you aware of?




Edited the example after ice-crime's answer



Edit: OK, thanks to the current answers I now know the theoretical purpose. But the questions are about practical uses so they still hold :)


Answer



You use a zero-length bitfield as a hacky way to get your compiler to lay out a structure to match some external requirement, be it another compiler's or architecture's notion of the layout (cross-platform data structures, such as in a binary file format) or a bit-level standard's requirements (network packets or instruction opcodes).



A real-world example is when NeXT ported the xnu kernel from the Motorola 68000 (m68k) architecture to the i386 architecture. NeXT had a working m68k version of their kernel. When they ported it to i386, they found that the i386's alignment requirements differed from the m68k's in such a way that an m68k machine and an i386 machine did not agree on the layout of the NeXT vendor-specific BOOTP structure. In order to make the i386 structure layout agree with the m68k, they added an unnamed bitfield of length zero to force the NV1 structure/nv_U union to be 16-bit aligned.



Here are the relevant parts from the Mac OS X 10.6.5 xnu source code:




/* from xnu/bsd/netinet/bootp.h */
/*
* Bootstrap Protocol (BOOTP). RFC 951.
*/
/*
* HISTORY
*
* 14 May 1992 ? at NeXT
* Added correct padding to struct nextvend. This is
* needed for the i386 due to alignment differences wrt

* the m68k. Also adjusted the size of the array fields
* because the NeXT vendor area was overflowing the bootp
* packet.
*/
/* . . . */
struct nextvend {
u_char nv_magic[4]; /* Magic number for vendor specificity */
u_char nv_version; /* NeXT protocol version */
/*
* Round the beginning

* of the union to a 16
* bit boundary due to
* struct/union alignment
* on the m68k.
*/
unsigned short :0;
union {
u_char NV0[58];
struct {
u_char NV1_opcode; /* opcode - Version 1 */

u_char NV1_xid; /* transcation id */
u_char NV1_text[NVMAXTEXT]; /* text */
u_char NV1_null; /* null terminator */
} NV1;
} nv_U;
};

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