Sunday, August 19, 2018

php - Check if value isset and null



I need to check if value is defined as anything, including null. isset treats null values as undefined and returns false. Take the following as an example:




$foo = null;

if(isset($foo)) // returns false
if(isset($bar)) // returns false
if(isset($foo) || is_null($foo)) // returns true
if(isset($bar) || is_null($bar)) // returns true, raises a notice


Note that $bar is undefined.




I need to find a condition that satisfies the following:



if(something($bar)) // returns false;
if(something($foo)) // returns true;


Any ideas?


Answer



IIRC, you can use get_defined_vars() for this:




$foo = NULL;
$vars = get_defined_vars();
if (array_key_exists('bar', $vars)) {}; // Should evaluate to FALSE
if (array_key_exists('foo', $vars)) {}; // Should evaluate to TRUE

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