inheritance - How to use base class's constructors and assignment operator in C++?

I have a class B with a set of constructors and an assignment operator.

Here it is:

class B
{
 public:
  B();
  B(const string& s);
  B(const B& b) { (*this) = b; }

  B& operator=(const B & b);

 private:
  virtual void foo();
  // and other private member variables and functions
};

I want to create an inheriting class D that will just override the function foo(), and no other change is required.

But, I want D to have the same set of constructors, including copy constructor and assignment operator as B:

D(const D& d) { (*this) = d; }
D& operator=(const D& d);

Do I have to rewrite all of them in D, or is there a way to use B's constructors and operator? I would especially want to avoid rewriting the assignment operator because it has to access all of B's private member variables.

Answer

You can explicitly call constructors and assignment operators:

class Base {
//...
public:
    Base(const Base&) { /*...*/ }
    Base& operator=(const Base&) { /*...*/ }
};

class Derived : public Base
{
    int additional_;

public:
    Derived(const Derived& d)
        : Base(d) // dispatch to base copy constructor
        , additional_(d.additional_)
    {
    }

    Derived& operator=(const Derived& d)
    {
        Base::operator=(d);

        additional_ = d.additional_;
        return *this;
    }
};

The interesting thing is that this works even if you didn't explicitly define these functions (it then uses the compiler generated functions).

class ImplicitBase { 
    int value_; 

    // No operator=() defined
};

class Derived : public ImplicitBase {
    const char* name_;
public:
    Derived& operator=(const Derived& d)
    {
         ImplicitBase::operator=(d); // Call compiler generated operator=
         name_ = strdup(d.name_);

         return *this;
    }
};